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Math for Machine Learning - Chapter 3: Linear Independence and Basis

Created by Shiju P John ยท 11/4/2025

๐Ÿ“š Subject

Math for Machine Learning

๐ŸŽ“ Exam

Any

๐Ÿ—ฃ Language

English

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Practice

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๐Ÿ“„ Description

This quiz rigorously tests your understanding of linear independence, span, basis, and dimension, crucial concepts in Linear Algebra for Machine Learning. It covers identifying redundant vectors, understanding coordinate systems, and implications for feature engineering and dimensionality reduction. Expect challenging questions that require a deep conceptual grasp and analytical skills.

Key Formulae and Concepts:

  • Linear Combination: A vector v\mathbf{v} is a linear combination of vectors v1,v2,โ€ฆ,vk\mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_k if there exist scalars c1,โ€ฆ,ckc_1, \ldots, c_k such that v=c1v1+c2v2+โ€ฆ+ckvk\mathbf{v} = c_1\mathbf{v}_1 + c_2\mathbf{v}_2 + \ldots + c_k\mathbf{v}_k.

  • Linear Independence: A set of vectors {v1,v2,โ€ฆ,vk}\{\mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_k\} is linearly independent if the only solution to the vector equation c1v1+c2v2+โ€ฆ+ckvk=0c_1\mathbf{v}_1 + c_2\mathbf{v}_2 + \ldots + c_k\mathbf{v}_k = \mathbf{0} is c1=c2=โ€ฆ=ck=0c_1 = c_2 = \ldots = c_k = 0. If non-zero scalars exist, the vectors are linearly dependent (redundant).

  • Span: The span of a set of vectors S={v1,v2,โ€ฆ,vk}S = \{\mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_k\}, denoted by span(S)\text{span}(S), is the set of all possible linear combinations of the vectors in SS.

  • Basis: A set of vectors B={b1,b2,โ€ฆ,bd}\mathcal{B} = \{\mathbf{b}_1, \mathbf{b}_2, \ldots, \mathbf{b}_d\} is a basis for a vector space VV if:

    1. B\mathcal{B} is linearly independent.

    2. span(B)=V\text{span}(\mathcal{B}) = V.

  • Dimension: The dimension of a vector space VV, denoted dim(V)\text{dim}(V), is the number of vectors in any basis for VV. All bases for a given finite-dimensional vector space have the same number of vectors.

  • Coordinate Vector: If B={b1,โ€ฆ,bn}\mathcal{B} = \{\mathbf{b}_1, \ldots, \mathbf{b}_n\} is a basis for VV, then for any xโˆˆV\mathbf{x} \in V, there exist unique scalars c1,โ€ฆ,cnc_1, \ldots, c_n such that x=c1b1+โ€ฆ+cnbn\mathbf{x} = c_1\mathbf{b}_1 + \ldots + c_n\mathbf{b}_n. The coordinate vector of x\mathbf{x} relative to B\mathcal{B} is [x]B=[c1โ‹ฎcn][\mathbf{x}]_{\mathcal{B}} = \begin{bmatrix} c_1 \\ \vdots \\ c_n \end{bmatrix}.

  • Determinant and Linear Independence: For nn vectors in Rn\mathbb{R}^n, they are linearly independent if and only if the determinant of the matrix formed by these vectors as columns (or rows) is non-zero.

  • Rank-Nullity Theorem: For an mร—nm \times n matrix AA, rank(A)+nullity(A)=n\text{rank}(A) + \text{nullity}(A) = n, where rank(A)\text{rank}(A) is the dimension of the column space (or row space) and nullity(A)\text{nullity}(A) is the dimension of the null space.

  • Properties:

    • Any set of kk vectors in an nn-dimensional space is linearly dependent if k>nk > n.

    • Any set of kk vectors in an nn-dimensional space cannot span the space if k<nk < n.

    • A set of vectors containing the zero vector is always linearly dependent.

๐Ÿท Tags

#Linear Algebra#Machine Learning#Linear Independence#Basis#Dimension#Vector Spaces#Subspaces#Span#Coordinate Systems

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